3v^2+46v+15=0

Solution for 3v^2+46v+15=0 equation:

3v^2+46v+15=0

a = 3; b = 46; c = +15;
Δ = b2-4ac
Δ = 462-4·3·15
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-44}{2*3}=\frac{-90}{6}
=-15
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+44}{2*3}=\frac{-2}{6}
=-1/3
$